力扣第191-位1的个数

题目
链接

题解

public class Solution {
    // you need to treat n as an unsigned value
    public int hammingWeight(int n) {
        int res = 0;
        for (int i = 0; i < 32; i++) {
            // 将1分别移动到对应的byte上和其与操作如果不等于0该位一定为1
            if ((n & (1 << i)) != 0) {
                res += 1;
            }
        }
        return res;
    }
}